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(123456789⼀123456788-123456788⼀123456789)÷(1⼀123456788+1⼀123456789)

简便算法
被浏览: 0次 2023年03月25日 03:47
热门回答(6个)
游客1

转换一下,a=123456788,b=123456789
原咐带式=(b/a-a/b)/衡局芦(1/腊桐a+1/b)
=[(b^2-a^2)/ab]/[(b+a)/ab]
=(b^2-a^2)/(b+a)
=(b+a)(b-a)/(b+a)
=b-a
=123456789-123456788
=1

游客2

X=123456789,123456788=X-1
原式=[X/(X-1)-(X-1)正芹/X]/[1/(X-1)+1/念带X]
=[(X²-(X-1)²举高毕)/(X(X-1))]/[(X+(X-1))/(X(X-1))]
=[X²-(X²-2X+1)]/[2X-1]
=(2X-1)/(2X-1)
= 1
答案与X无关

游客3

设羡前敬 123456789 = a, 123456788 = b;
则原式变作
( a/b - b/a ) / ( 1/b + 1/a ) = ( a^2 - b^2) / ab * ab / ( a + b) = a - b = 123456789 - 123456788 = 1;

答案是1,
正确的话 给个最佳答案,码字不容兄慎易悔举呢

游客4

原式=(1 1/123456788-1 1/123456789)/(1/123456788 1/123456789)=1
简便算法的核心局基渣就是把分子分离一下化锋橡简 如123456789/桐悄123456788=(123456788 1)/123456788

游客5

(123456789/123456788-123456788/123456789)÷(1/亮困碰123456788+1/123456789)
=(1+1/123456788-1+1/尺基123456789)÷(1/123456788+1/敬谈123456789)
=(1/123456788+1/123456789)÷(1/123456788+1/123456789)
=1

游客6

(123456789/123456788-123456788/123456789)÷(1/123456788+1/123456789)

=[(123456789^2-123456788^2)/(123456788*123456789)]/镇宏[(123456788+123456789)/(123456788*123456789)]

=(123456789^2-123456788^2)/团旅仿塌纤(123456788+123456789)

=123456789-123456788=1